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Draw the Lewis structure of (CHO)OCH₃ and then choose the appropriate set of molecular geometries of the three central atoms. Your answer choice is independent of the orientation of your drawn structure.

The solubility of He in water at 25.0 °C is 7.0 × 10⁻⁵ M when the partial pressure of He is 0.20 atm. What is the value of the Henry's law constant for He ?

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chem 101 homework 4 answers

According to the balanced reaction below, calculate the moles of NH₃ that form when 4.2 mol of N₂H₄ completely reacts 3 N₂H₄(l) → 4 NH₃(g) + N₂(g)

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4.E: Homework Chapter 4 Answers

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1.      All matter is composed of atoms; atoms of the same element are the same, and atoms of different elements are different; atoms combine in whole-number ratios to form compounds.

3.       

a.    Sodium---alkali metal

b. Magnesium---Alkaline earth metal

c.  Calcium---Alkaline earth metal

d.  Chlorine---halogen

e.  Potassium---Alkali metal

5.      Most of the alpha particles went through the metal sheet because atoms are mostly empty space.

7.      Electrons are in orbit about the nucleus.

9.      The electron weighs the least.  The protons and neutrons are found in the nucleus while electrons are located outside the nucleus.

11.  Proton, electron

13.  Least, outside

15.  a. Z = 8; O; atomic oxygen      

     b. Z = 27; Co; cobalt      

c. Z = 33; As; arsenic

e. Z = 90; Th; thorium

17.   a. P        b. Mo     c. Be

19.   a. Ag        b. S          c. N         d. Ne

21.  a. 86 b. 74 c. 24   d. 4

23.  Column 1 is the alkali metals.  Column 2 is the alkaline earth metals.  Columns 3 - 12              are the transition metals.

25.  The transition metals can exist in more than one charge state.  They have variable charge.

27.   Calcium and Barium (belong to same group).

29.  Magnesium; Beryllium

31.  Helium; Xenon; Neon

33.   metal; transition metal.

35.  a,d

37.  a. 1A (1) b. 1A (1) c. 8A (18) d. 6A (16)

39.   

41.  a and d

43.  a and b

45.  a. 27    b. 38      c. 54     d. 28

47.  a. 10    b. 2         c. 46     d. 30

49.  a.  Li, Li + , 2nd period, group 1

b.      F, F – , 2nd period, group 17

c.       Al, Al 3+ , 3nd period, group 13

51.   a. 2       b. 3          c. 3         d. 1

53.   

a.       1+

b.      2−

c.       2+, 3+

55.  SO 3  is sulfur trioxide, while SO 3 2−  is the sulfite ion.

57.   All isotopes of nitrogen have the same atomic number (Z = 7).  Yes, all isotopes of the same element have the same Z.

59.   a. Z=1, A=3       b. Z=20, A=42       c. Z=73, A=182          d. Z=24, A=52

61.  a.  26      b. 22      c. 2

63. a.          b.           c.      d.        e.

65.   

a.       protons=43; neutrons=54; electrons=43

b.      protons=49; neutrons=64; electrons=49

c.       protons=28; neutrons=35; electrons=28

d.      protons=26; neutrons=29; electrons=26

67.   

a.       protons=82; neutrons=125; electrons=82

b.        protons=8; neutrons=8; electrons=8

c.         protons=55; neutrons=82; electrons=55

d.      protons=19; neutrons=21; electrons=19

69.  This iron atom has 26 protons and 56 − 26 = 30 neutrons.

71.   a. He    b. B          c. Bi & P

73.   

  

75.  If "CO" was written as the chemical symbol for cobalt, it would be the same as the chemical formula for carbon monoxide. This ambiguity would create a lot problems such as in labeling and might lead to life-threatening danger. And The chemical symbol is  ALWAYS  written with the  first letter in uppercase and the second letter in lowercase.

77.   a) Iron, 26 protons, 24 electrons, and 32 neutrons;

     (b) iodine, 53 protons, 54 electrons, and 74 neutrons

79.   If the atomic number of uranium is 92, then that is the number of protons in the nucleus. Because the mass number is 235, then the number of neutrons in the nucleus is 235 − 92, or 143.

Wyzant

Chem 101 Homework 9: Rate Laws Question 4

Consider the radioisotope ²²⁶Ra (half life = 1.60 × 10³ years). What is the first order rate constant for ²²⁶Ra?

Answer= ______1/years

1 Expert Answer

chem 101 homework 4 answers

J.R. S. answered • 03/11/22

Ph.D. University Professor with 10+ years Tutoring Experience

For a first order reaction, t 1/2 = ln2/k = 0.693/k

1.60x10 3 yrs = 0.693/k

k= 4.3x10 -4 yrs -1

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